纏論中樞可以自動標識嗎 [文華財經]
-
咨詢內容：
?下面是纏論劃線的代碼可以加上中樞代碼嗎？一段盤整，自動根據劃線，高點的最低點，低點的最高點，自動畫出中樞 源碼：
M:=5;//M值需要大于等于5G:=MA(C,5);D:=MA(C,10);NNH:=BARSLAST(H=HHV(H,M)) ,NODRAW;NNL:=BARSLAST(L=LLV(L,M)) ,NODRAW;NN:=IF(REF(G,NNH)>REF(D,NNH) AND NNH<=M-3,NNH,IF(REF(G,NNL)<REF(D,NNL) AND NNL<=M-3,NNL,M-2)) ,NODRAW;NNN:=IF(ISLASTBAR AND NN>0,NN,M-2) ,NODRAW;H1:=REF(H,NNN)=HHV(H,M-1);L1:=REF(L,NNN)=LLV(L,M-1);FG01:=BACKSET(H1,NNN+1)>BACKSET(H1,NNN),NODRAW;//只設置前面第M-1個FD01:=BACKSET(L1,NNN+1)>BACKSET(L1,NNN) ,NODRAW;FG02:=FG01=FD01 AND G>D,NODRAW;FD02:=FG01=FD01 AND G<D,NODRAW;TTTT:=BARSLAST(FD01),NODRAW;FG0:=FG01 AND IF(FG02=1,H=HHV(H,BARSLAST(REF(FD01,1))+1),H=HHV(H,IF(BARSLAST(L=LLV(L,M))>=M-2,M-2,BARSLAST(FD01)))) AND FD02=0 ,NODRAW;FD0:=FD01 AND IF(FD02=1,L=LLV(L,BARSLAST(REF(FG01,1))+1),L=LLV(L,IF(BARSLAST(H=HHV(L,M))>=M-2,M-2,BARSLAST(FG01))))? AND FG02=0 ,NODRAW;//高低點間周期GT:=BARSLAST(FG0),NODRAW;DT:=BARSLAST(FD0),NODRAW;//第一次處理高低點間多余的點LLLL:=DT=0 AND REF(DT,1)<GT AND L>REF(L,REF(DT,1)+1),NODRAW;FG1:=BACKSET(REFX(GT,1)=0 AND GT<DT AND REFX(H,1)>=REF(H,GT),GT+1),NODRAW;FD1:=BACKSET(REFX(DT,1)=0 AND DT<GT AND REFX(L,1)<=REF(L,DT),DT+1),NODRAW;FG11:=IF(GT=0 AND REF(GT,1)<DT AND IF(REF(G,BARSLAST(L=LLV(L,M)))>REF(D,BARSLAST(L=LLV(L,M))),BARSLAST(L=LLV(L,M))<M-2,1) AND? H<REF(H,REF(GT,1)+1),1,0),NODRAW;FD11:=IF(DT=0 AND REF(DT,1)<GT AND IF(REF(G,BARSLAST(H=HHV(H,M)))<REF(D,BARSLAST(H=HHV(H,M))),BARSLAST(H=HHV(H,M))<M-2,1) AND L>REF(L,REF(DT,1)+1),1,0),NODRAW;//再次周期GT1:=BARSLAST(FG11<>1 AND FG1<>1 AND FG0),NODRAW;DT1:=BARSLAST(FD11<>1 AND FD1<>1 AND FD0),NODRAW;FD2:=BACKSET(REFX(GT1,1)=0 AND DT1<3 AND GT1-DT1<4 AND REF(L,DT1)>LLV(L,GT1+M-2),DT1+1),NODRAW;FG2A:=BACKSET(REFX(GT1,1)=0 AND DT1<3 AND GT1-DT1<4 AND REF(L,DT1)<=LLV(L,GT1+M-2) AND REF(H,GT1)>HHV(H,GT1+M-2),GT1+1),NODRAW;FG2B:=IF(GT1=0 AND DT1<4 AND REF(GT1,1)-DT1<4 AND REF(L,DT1)<=LLV(L,REF(GT1,1)+M-1) AND H>HHV(H,REF(GT1,1)+M-1),1,0),NODRAW;FG2:=BACKSET(REFX(DT1,1)=0 AND GT1<3 AND DT1-GT1<4 AND REF(H,GT1)<HHV(H,DT1+M-2),GT1+1),NODRAW;FD2A:=BACKSET(REFX(DT1,1)=0 AND GT1<3 AND DT1-GT1<4 AND REF(H,GT1)>=HHV(L,DT1+M-2) AND REF(L,DT1)>LLV(L,DT1+M-2),DT1+1),NODRAW;FD2B:=IF(DT1=0 AND GT1<4 AND REF(DT1,1)-GT1<4 AND REF(H,GT1)>=HHV(H,REF(DT1,1)+6) AND L>LLV(L,REF(DT1,1)+M-1),1,0),NODRAW;TTTTTT:= H<REF(H,REF(GT1,1)+1) AND DT1<4,NODRAW;HHHHHH:=REF(LLV(L,10),DT1),NODRAW;//前長后短;FG21:=IF(GT1=0 AND DT1<4 AND H<=REF(H,REF(GT1,1)+1)? ,1,0),NODRAW;FD21:=IF(DT1=0 AND GT1<4? AND L>=REF(L,REF(DT1,1)+1) ,1,0),NODRAW;//前短后長,前低后高（去低）;FD231:=BACKSET(REFX(GT1,1)=0 AND DT1>3 AND GT1>DT1 AND GT1-DT1<4 AND REFX(H,1)>REF(H,GT1) AND REF(L,DT1)>REF(LLV(L,10),DT1),DT1+1),NODRAW;FG23:=BACKSET(REFX(GT1,1)=0 AND DT1>3 AND GT1>DT1 AND? GT1-DT1<4 AND REFX(H,1)>REF(H,GT1) AND (REF(H,GT1)<REF(HHV(H,13),GT1) OR REF(FD231,DT1)=0),GT1+1),NODRAW;//前短后長，去2;FG231:=BACKSET(REFX(DT1,1)=0 AND GT1>3? AND DT1>GT1 AND DT1-GT1<4 AND REFX(L,1)<REF(L,DT1) AND REF(H,GT1)<REF(HHV(H,10),GT1) ,GT1+1),NODRAW;FD23:=BACKSET(REFX(DT1,1)=0 AND GT1>3? AND DT1>GT1 AND DT1-GT1<4 AND REFX(L,1)<REF(L,DT1) AND ( REF(L,DT1)>REF(LLV(L,13),DT1) OR REF(FG231,GT1)=0),DT1+1),NODRAW;//前短后長，去3;FDD23:=REF(H,GT1)<REF(HHV(H,10),GT1) OR REF(FD23,DT1)=0,NODRAW;FD24:=BACKSET(REFX(GT1,1)=0 AND DT1>3 AND GT1>DT1 AND GT1-DT1<4 AND REFX(H,1)<HHV(H,GT1+3) AND REF(L,DT1)>LLV(L,DT1+5),DT1+1),NODRAW;FG24:=BACKSET(REFX(DT1,1)=0 AND GT1>3? AND DT1>GT1 AND DT1-GT1<4 AND REFX(L,1)>LLV(L,DT1+3) AND REF(H,GT1)<HHV(H,GT1+5),GT1+1),NODRAW;//做兩次高低點間多余的點GT2:=BARSLAST(FG21<>1 AND FG23<>1 AND FG231<>1 AND FG24<>1? ?AND FG2<>1 AND FG2A<>1 AND FG2B<>1 AND GT1=0),NODRAW;DT2:=BARSLAST(FD21<>1 AND FD23<>1 AND FD231<>1 AND FD24<>1? AND FD2<>1 AND FD2A<>1 AND FD2B<>1 AND DT1=0),NODRAW;FG3:=BACKSET(REFX(GT2,1)=0 AND GT2<DT2 AND REFX(H,1)>=REF(H,GT2),GT2+1),NODRAW;FD3:=BACKSET(REFX(DT2,1)=0 AND DT2<GT2 AND REFX(L,1)<=REF(L,DT2),DT2+1),NODRAW;FG31:=IF(GT2=0 AND REF(GT2,1)<DT2 AND H<REF(H,REF(GT2,1)+1),1,0),NODRAW;FD31:=IF(DT2=0 AND REF(DT2,1)<GT2 AND L>REF(L,REF(DT2,1)+1),1,0),NODRAW;GT3:=BARSLAST(GT2=0 AND FG3<>1 AND FG31<>1 ),NODRAW;DT3:=BARSLAST(DT2=0 AND? FD3<>1 AND FD31<>1),NODRAW;FG4:=BACKSET(REFX(GT3,1)=0 AND GT3<DT3 AND REFX(H,1)>=REF(H,GT3),GT3+1),NODRAW;FD4:=BACKSET(REFX(DT3,1)=0 AND DT3<GT3 AND REFX(L,1)<=REF(L,DT3),DT3+1),NODRAW;FG41:=IF(GT3=0 AND REF(GT3,1)<DT3 AND H<REF(H,REF(GT3,1)+1),1,0),NODRAW;FD41:=IF(DT3=0 AND REF(DT3,1)<GT3 AND L>REF(L,REF(DT3,1)+1),1,0),NODRAW;HHH:=GT3=0 AND FG31<>1 AND? FG3<>1,NODRAW;LLL:=DT3=0 AND FD31<>1 AND? FD3<>1,NODRAW;DRAWLINE1(HHH ,H,LLL,L,0),COLORGREEN,LINETHICK3;//綠色DRAWLINE1(LLL,L,HHH ,H,0),COLORRED,LINETHICK3;//紅色//最后一段畫線N1:=BARSLAST(HHH)+1;N2:=BARSLAST(LLL)+1;DRAWLINE3(ISLASTBAR&&MIN(N1,N2)=N2&&L>REF(L,N2-1),REF(L,N2-1),N2-1,ISLASTBAR,H,0,0),COLORRED,LINETHICK3;//紅色DRAWLINE3(ISLASTBAR&&MIN(N1,N2)=N1&&H<REF(H,N1-1),REF(H,N1-1),N1-1,ISLASTBAR,L,0,0),COLORGREEN,LINETHICK3;//綠色?
?來源:程序化99
- 文華技術人員： ?纏論中樞編寫復雜，?來源:程序化99
- 文華技術人員：不屬于論壇免費服務的范疇，論壇不提供編寫。
有思路，想編寫各種指標公式，交易模型，選股公式，還原公式的朋友
可聯系技術人員 QQ: 262069696 或微信號：cxh99cxh99 進行 有償收費 編寫！
(注：由于人數限制，QQ或微信請選擇方便的一個聯系我們就行，加好友時請簡單備注下您的需求，否則無法通過。謝謝您！)
相關文章
-
沒有相關內容