咨詢內容：
你好，改成適合博弈的函數，謝謝
M:=5;//M值需要大于等于5
G:=MA(C,5);
D:=MA(C,10);
NNH:=BARSLAST(H=HHV(H,M)) ,NODRAW;
NNL:=BARSLAST(L=LLV(L,M)) ,NODRAW;
NN:=IF(REF(G,NNH)>REF(D,NNH) AND NNH<=M-3,NNH,IF(REF(G,NNL)<REF(D,NNL) AND NNL<=M-3,NNL,M-2)) ,NODRAW;
NNN:=IF(ISLASTBAR AND NN>0,NN,M-2) ,NODRAW;
H1:=REF(H,NNN)=HHV(H,M-1);
L1:=REF(L,NNN)=LLV(L,M-1);
FG01:=BACKSET(H1,NNN+1)>BACKSET(H1,NNN),NODRAW;//只設置前面第M-1個
FD01:=BACKSET(L1,NNN+1)>BACKSET(L1,NNN) ,NODRAW;
FG02:=FG01=FD01 AND G>D,NODRAW;
FD02:=FG01=FD01 AND G<D,NODRAW;
TTTT:=BARSLAST(FD01),NODRAW;
FG0:=FG01 AND IF(FG02=1,H=HHV(H,BARSLAST(REF(FD01,1))+1),H=HHV(H,IF(BARSLAST(L=LLV(L,M))>=M-2,M-2,BARSLAST(FD01)))) AND FD02=0 ,NODRAW;
FD0:=FD01 AND IF(FD02=1,L=LLV(L,BARSLAST(REF(FG01,1))+1),L=LLV(L,IF(BARSLAST(H=HHV(L,M))>=M-2,M-2,BARSLAST(FG01)))) AND FG02=0 ,NODRAW;?
//高低點間周期
GT:=BARSLAST(FG0),NODRAW;
DT:=BARSLAST(FD0),NODRAW;?
//第一次處理高低點間多余的點
LLLL:=DT=0 AND REF(DT,1)<GT AND L>REF(L,REF(DT,1)+1),NODRAW;
FG1:=BACKSET(REFX(GT,1)=0 AND GT<DT AND REFX(H,1)>=REF(H,GT),GT+1),NODRAW;
FD1:=BACKSET(REFX(DT,1)=0 AND DT<GT AND REFX(L,1)<=REF(L,DT),DT+1),NODRAW;
FG11:=IF(GT=0 AND REF(GT,1)<DT AND IF(REF(G,BARSLAST(L=LLV(L,M)))>REF(D,BARSLAST(L=LLV(L,M))),BARSLAST(L=LLV(L,M))<M-2,1) AND H<REF(H,REF(GT,1)+1),1,0),NODRAW;
FD11:=IF(DT=0 AND REF(DT,1)<GT AND IF(REF(G,BARSLAST(H=HHV(H,M)))<REF(D,BARSLAST(H=HHV(H,M))),BARSLAST(H=HHV(H,M))<M-2,1) AND L>REF(L,REF(DT,1)+1),1,0),NODRAW;?
//再次周期
GT1:=BARSLAST(FG11<>1 AND FG1<>1 AND FG0),NODRAW;
DT1:=BARSLAST(FD11<>1 AND FD1<>1 AND FD0),NODRAW;
FD2:=BACKSET(REFX(GT1,1)=0 AND DT1<3 AND GT1-DT1<4 AND REF(L,DT1)>LLV(L,GT1+M-2),DT1+1),NODRAW;
FG2A:=BACKSET(REFX(GT1,1)=0 AND DT1<3 AND GT1-DT1<4 AND REF(L,DT1)<=LLV(L,GT1+M-2) AND REF(H,GT1)>HHV(H,GT1+M-2),GT1+1),NODRAW;
FG2B:=IF(GT1=0 AND DT1<4 AND REF(GT1,1)-DT1<4 AND REF(L,DT1)<=LLV(L,REF(GT1,1)+M-1) AND H>HHV(H,REF(GT1,1)+M-1),1,0),NODRAW;
FG2:=BACKSET(REFX(DT1,1)=0 AND GT1<3 AND DT1-GT1<4 AND REF(H,GT1)<HHV(H,DT1+M-2),GT1+1),NODRAW;
FD2A:=BACKSET(REFX(DT1,1)=0 AND GT1<3 AND DT1-GT1<4 AND REF(H,GT1)>=HHV(L,DT1+M-2) AND REF(L,DT1)>LLV(L,DT1+M-2),DT1+1),NODRAW;
FD2B:=IF(DT1=0 AND GT1<4 AND REF(DT1,1)-GT1<4 AND REF(H,GT1)>=HHV(H,REF(DT1,1)+6) AND L>LLV(L,REF(DT1,1)+M-1),1,0),NODRAW;
TTTTTT:= H<REF(H,REF(GT1,1)+1) AND DT1<4,NODRAW;
HHHHHH:=REF(LLV(L,10),DT1),NODRAW;?
//前長后短;
FG21:=IF(GT1=0 AND DT1<4 AND H<=REF(H,REF(GT1,1)+1) ,1,0),NODRAW;
FD21:=IF(DT1=0 AND GT1<4 AND L>=REF(L,REF(DT1,1)+1) ,1,0),NODRAW;?
//前短后長,前低后高（去低）;
FD231:=BACKSET(REFX(GT1,1)=0 AND DT1>3 AND GT1>DT1 AND GT1-DT1<4 AND REFX(H,1)>REF(H,GT1) AND REF(L,DT1)>REF(LLV(L,10),DT1),DT1+1),NODRAW;
FG23:=BACKSET(REFX(GT1,1)=0 AND DT1>3 AND GT1>DT1 AND GT1-DT1<4 AND REFX(H,1)>REF(H,GT1) AND (REF(H,GT1)<REF(HHV(H,13),GT1) OR REF(FD231,DT1)=0),GT1+1),NODRAW;?
//前短后長，去2;
FG231:=BACKSET(REFX(DT1,1)=0 AND GT1>3 AND DT1>GT1 AND DT1-GT1<4 AND REFX(L,1)<REF(L,DT1) AND REF(H,GT1)<REF(HHV(H,10),GT1) ,GT1+1),NODRAW;
FD23:=BACKSET(REFX(DT1,1)=0 AND GT1>3 AND DT1>GT1 AND DT1-GT1<4 AND REFX(L,1)<REF(L,DT1) AND ( REF(L,DT1)>REF(LLV(L,13),DT1) OR REF(FG231,GT1)=0),DT1+1),NODRAW;?
//前短后長，去3;
FDD23:=REF(H,GT1)<REF(HHV(H,10),GT1) OR REF(FD23,DT1)=0,NODRAW;
FD24:=BACKSET(REFX(GT1,1)=0 AND DT1>3 AND GT1>DT1 AND GT1-DT1<4 AND REFX(H,1)<HHV(H,GT1+3) AND REF(L,DT1)>LLV(L,DT1+5),DT1+1),NODRAW;
FG24:=BACKSET(REFX(DT1,1)=0 AND GT1>3 AND DT1>GT1 AND DT1-GT1<4 AND REFX(L,1)>LLV(L,DT1+3) AND REF(H,GT1)<HHV(H,GT1+5),GT1+1),NODRAW;?
//做兩次高低點間多余的點
GT2:=BARSLAST(FG21<>1 AND FG23<>1 AND FG231<>1 AND FG24<>1 AND FG2<>1 AND FG2A<>1 AND FG2B<>1 AND GT1=0),NODRAW;
DT2:=BARSLAST(FD21<>1 AND FD23<>1 AND FD231<>1 AND FD24<>1 AND FD2<>1 AND FD2A<>1 AND FD2B<>1 AND DT1=0),NODRAW;
FG3:=BACKSET(REFX(GT2,1)=0 AND GT2<DT2 AND REFX(H,1)>=REF(H,GT2),GT2+1),NODRAW;
FD3:=BACKSET(REFX(DT2,1)=0 AND DT2<GT2 AND REFX(L,1)<=REF(L,DT2),DT2+1),NODRAW;
FG31:=IF(GT2=0 AND REF(GT2,1)<DT2 AND H<REF(H,REF(GT2,1)+1),1,0),NODRAW;
FD31:=IF(DT2=0 AND REF(DT2,1)<GT2 AND L>REF(L,REF(DT2,1)+1),1,0),NODRAW;
GT3:=BARSLAST(GT2=0 AND FG3<>1 AND FG31<>1 ),NODRAW;
DT3:=BARSLAST(DT2=0 AND FD3<>1 AND FD31<>1),NODRAW;
FG4:=BACKSET(REFX(GT3,1)=0 AND GT3<DT3 AND REFX(H,1)>=REF(H,GT3),GT3+1),NODRAW;
FD4:=BACKSET(REFX(DT3,1)=0 AND DT3<GT3 AND REFX(L,1)<=REF(L,DT3),DT3+1),NODRAW;
FG41:=IF(GT3=0 AND REF(GT3,1)<DT3 AND H<REF(H,REF(GT3,1)+1),1,0),NODRAW;
FD41:=IF(DT3=0 AND REF(DT3,1)<GT3 AND L>REF(L,REF(DT3,1)+1),1,0),NODRAW;
HHH:=GT3=0 AND FG31<>1 AND FG3<>1,NODRAW;
LLL:=DT3=0 AND FD31<>1 AND FD3<>1,NODRAW;
DRAWLINE1(HHH ,H,LLL,L,0),COLORCYAN,LINETHICK1;//青色
DRAWLINE1(LLL,L,HHH ,H,0),COLORCYAN,LINETHICK1;//青色?
//最后一段畫線
N1:=BARSLAST(HHH)+1;
N2:=BARSLAST(LLL)+1;
DRAWLINE3(ISLASTBAR&&MIN(N1,N2)=N2&&L>REF(L,N2-1),REF(L,N2-1),N2-1,ISLASTBAR,H,0,0),COLORRED,LINETHICK1;//紅色
DRAWLINE3(ISLASTBAR&&MIN(N1,N2)=N1&&H<REF(H,N1-1),REF(H,N1-1),N1-1,ISLASTBAR,L,0,0),COLORGREEN,LINETHICK1;//綠色
?
?來源:程序化99網（ www.tumamayizhan.com ）
博易技術人員：
您好，很多函數不匹配，無法修改
是嗎？專業人士也搞不定。
來源 程序化久久網
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