是不是這個.

MA(C,5)>REF(MA(C,5),1)&&MA(C,10)>REF(MA(C,10),1)&&MA(C,20)>REF(MA(C,20),1)&&MA(C,5)>MA(C,10)&&MA(C,10)>MA(C,20)&&HSL>3.8&&COUNT(C>O,5)>=3;