函數不能在IF控制語句中被引用的原理和解決方案　[金字塔]

金字塔的公式系統在處于逐周期模式計算時，像例如REF,MA等帶有統計性質的函數以及指標公式引用無法直接使用在IF語句之中（序列運行模式可以），因為帶變量判斷的IF語句會在某些周期無法調用這些統計函數而導致計算結果出現錯誤。解決辦法是將這些函數放到IF語句之外去執行。
目前有下列函數受此限制:

"RET","LOD","HOD","VALUEWHEN","MD","LAST","ANY","SETVAL","FILTERX","BARSCOUNT","BARSLAST","BARSSINCE","COUNT","HHV","HHVBARS","LLV","LLVBARS",
"MA","DMA","EMA","FILTER","REF","WMA","TMA","SMA","SUM","SUMBARS","CROSS","LONGCROSS","AVEDEV","DEVSQ","FORCAST","SLOPE","STD","STDP","VAR","VARP","SAR","BETA","COVAR","ALL",
"BACKSET","REFX","PARTLINE","SFILTER","RELATE","ALIKE","FILLRGN","NEWHBARS","NEWLBARS","DRL","GEOMEAN","HARMEAN","KURT","SKEW","PEARSON","RSQ",
"STEYX","INTERCEPT"

例如：

input:atrn1(1,1,10),atrn2(5,2,20);

if atrn1<atrn2 and vol>20000 then
begin
    TR1:= MAX(MAX((HIGH-LOW),ABS(REF(CLOSE,1)-HIGH)),ABS(REF(CLOSE,1)-LOW));
    ATRn_1:= MA(TR1,atrn1);
    ATRn_2:= MA(TR1,atrn2);
end;

上述公式語句由于將REF和MA函數放在了IF語句之中，所以該公式無法正常編譯。解決辦法是將他們放到IF語句之外去執行:

input:atrn1(1,1,10),atrn2(5,2,20);

A1:=REF(CLOSE,1);
MA1:=MA(TR1,atrn1);
MA2:=MA(TR1,atrn2);

if atrn1<atrn2 and vol>20000 then
begin
    TR1:= MAX(MAX((HIGH-LOW),ABS(A1-HIGH)),ABS(A1-LOW));
    ATRn_1:= MA1;
    ATRn_2:= MA2;
end;

這樣經過修正的公式就可以正常編譯了，此外公式還將兩次REF語句引用合并到一個語句中，這樣做還可以提高公式系統的運行效率，因為REF統計語句只執行了一次。

金字塔的公式系統由于支持IF語句的變量運行，所以像例如REF,MA等帶有統計性質的函數無法直接使用在IF語句之中，因為帶變量判斷的IF語句會在某些周期無法調用這些統計函數而導致計算結果出現錯誤。解決辦法是將這些函數放到IF語句之外去執行。
目前有下列函數受此限制:

"RET","LOD","HOD","VALUEWHEN","MD","LAST","ANY","SETVAL","FILTERX","BARSCOUNT","BARSLAST","BARSSINCE","COUNT","HHV","HHVBARS","LLV","LLVBARS",
"MA","DMA","EMA","FILTER","REF","WMA","TMA","SMA","SUM","SUMBARS","CROSS","LONGCROSS","AVEDEV","DEVSQ","FORCAST","SLOPE","STD","STDP","VAR","VARP","SAR","BETA","COVAR","ALL",
"BACKSET","REFX","PARTLINE","SFILTER","RELATE","ALIKE","FILLRGN","NEWHBARS","NEWLBARS"

例如：

input:atrn1(1,1,10),atrn2(5,2,20);

if atrn1<atrn2 and vol>20000 then
begin
    TR1:= MAX(MAX((HIGH-LOW),ABS(REF(CLOSE,1)-HIGH)),ABS(REF(CLOSE,1)-LOW));
    ATRn_1:= MA(TR1,atrn1);
    ATRn_2:= MA(TR1,atrn2);
end;

上述公式語句由于將REF和MA函數放在了IF語句之中，所以該公式無法正常編譯。解決辦法是將他們放到IF語句之外去執行:

input:atrn1(1,1,10),atrn2(5,2,20);

A1:=REF(CLOSE,1);
MA1:=MA(atrn1,atrn1);
MA2:=MA(atrn2,atrn2);

if atrn1<atrn2 and vol>20000 then
begin
    TR1:= MAX(MAX((HIGH-LOW),ABS(A1-HIGH)),ABS(A1-LOW));
    ATRn_1:= MA1;
    ATRn_2:= MA2;
end;

這樣經過修正的公式就可以正常編譯了，此外公式還將兩次REF語句引用合并到一個語句中，這樣做還可以提高公式系統的運行效率，因為REF統計語句只執行了一次。

input:atrn1(1,1,10),atrn2(5,2,20);

A1:=REF(CLOSE,1);
MA1:=MA(atrn1,atrn1);
MA2:=MA(atrn2,atrn2);

if atrn1<atrn2 and vol>20000 then
begin
    TR1:= MAX(MAX((HIGH-LOW),ABS(A1-HIGH)),ABS(A1-LOW));
    ATRn_1:= MA1;
    ATRn_2:= MA2;
end;
這紅色的語句有問題吧

呵呵呵，你好眼力，是筆誤。自己看幫助就知道了。。。。。

還有一處好象有問題！

input:atrn1(1,1,10),atrn2(5,2,20);

A1:=REF(CLOSE,1);
MA1:=MA(tr1,atrn1);  //語句順序錯了！這樣tr1會提示沒有定義的！應直接把TR1:= MAX(MAX((HIGH-LOW),ABS(A1-HIGH)),ABS(A1-LOW));也放在IF語句外面，并在MA1前面！
MA2:=MA(tr1,atrn2);

if atrn1<atrn2 and vol>20000 then
begin
    TR1:= MAX(MAX((HIGH-LOW),ABS(A1-HIGH)),ABS(A1-LOW));
    ATRn_1:= MA1;
    ATRn_2:= MA2;
end;